In a comparison of an 8-inch line to a 6-inch line over 500 feet, what is the approximate percent volume reduction?

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Multiple Choice

In a comparison of an 8-inch line to a 6-inch line over 500 feet, what is the approximate percent volume reduction?

Explanation:
The main idea is that, for pipes of the same length, the volume (or capacity) scales with the cross-sectional area, and for a circular pipe that area is proportional to the square of the diameter. So compare volumes by squaring the diameters. Compute the volume ratio: V6/V8 = (6^2)/(8^2) = 36/64 = 0.5625. This means the 6-inch line has about 56% of the 8-inch line’s volume. The decrease from 8 inches to 6 inches is 1 − 0.5625 = 0.4375, which is 43.75%, roughly 44%. So the approximate percent volume reduction is 44%. The other options don’t match this squared-diameter relationship (they’d correspond to the ratio itself rather than the reduction).

The main idea is that, for pipes of the same length, the volume (or capacity) scales with the cross-sectional area, and for a circular pipe that area is proportional to the square of the diameter. So compare volumes by squaring the diameters.

Compute the volume ratio: V6/V8 = (6^2)/(8^2) = 36/64 = 0.5625. This means the 6-inch line has about 56% of the 8-inch line’s volume. The decrease from 8 inches to 6 inches is 1 − 0.5625 = 0.4375, which is 43.75%, roughly 44%.

So the approximate percent volume reduction is 44%. The other options don’t match this squared-diameter relationship (they’d correspond to the ratio itself rather than the reduction).

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